[123]⋅[321]\displaystyle \left [ \begin{matrix} 1 \\ 2 \\ 3 \end{matrix} \right ] \cdot \left [ \begin{matrix} 3 & 2 & 1 \end{matrix} \right ]⎣⎡123⎦⎤⋅[321]
[321]⋅[123]=[3⋅1+2⋅2+1⋅3]=[10]=10\displaystyle \left [ \begin{matrix} 3 & 2 & 1 \end{matrix} \right ] \cdot \left [ \begin{matrix} 1 \\ 2 \\ 3 \end{matrix} \right ] = \left [ 3 \cdot 1 + 2 \cdot 2 + 1 \cdot 3 \right ] = \left [ 10 \right ] = 10[321]⋅⎣⎡123⎦⎤=[3⋅1+2⋅2+1⋅3]=[10]=10
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